Bypass Caps?

[Rock_on]

am i right? pin 2 goes to + of cap then pin 1 goes to - of the cap then emitter pin to 3 then ground to pin 2??

like this one here?


cause i thought if ground in on pin 1 and emitter on pin 3... then nothing will be connected? you guys get what i mean?

[IvIark]

Lug 3 of the pot to emitter
Lug 2 of the pot to 22u +
Lug 1 of the pot and 22u - to ground

The pot alters the resistance between the cap and the emitter.

[Rock_on]

Lug 3 of the pot to emitter
Lug 2 of the pot to 22u +
Lug 1 of the pot and 22u - to ground

The pot alters the resistance between the cap and the emitter.

thanks... i thought i should put the ground to 2.. well i did try and it's working.. i'll just do the proper one.. like the one you say

[Rock_on]

Idk why but it's frustrating.. Sometimes it's working sometimes not and i need to find the place for the pot to work (twisting the wires, moving it up and down, etc)


Im thinking of

1 and 2 tied then - of cap going to ground

3 and + of cap to emitter..

Will it work??

[ashcat_lt]

Pretty sure you want to leave the DC resistance from the emitter to ground alone, or else you'll be messing up your bias or something.  That's why ground is always at the other end of the pot, rather than on the wiper.  The cap between wiper and ground allows the AC impedance to change (and AC gain along with it) while the DC component sees only the one, static resistance at all times.

[Gus]

OK another TEST for the "designers"

what does D2 do?
Note it is DC coupled not AC coupled and D2 is not a lower forward voltage drop diode like a schottky
http://en.wikipedia.org/wiki/Baker_clamp

[Kipper4]

Not hyjacking but i'm a newbie and i want to learn.
What is a bypass cap and how does it work in this circuit please explain so i might learn something thanks