Hex inverter DIP8 package?

Started by Chugs, August 25, 2018, 07:28:20 AM

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Rob Strand

#20
I don't know why but I checked the datasheet for the CD40107.    The datasheet says it's a *NAND* gate.   the chip's identity has morphed over the thread from an inverter to the NOR gate.  You should update the schematic.

So that means on the reset circuit you need to connect the R to VCC and the C to ground.
Also, the output of the gate which has the reset circuit connected will go *high*  at power-up.
The LED goes on when the output goes low, so the LED  which you want to come on at power-up
is the gate *without* the reset circuit connected it.
Send:     . .- .-. - .... / - --- / --. --- .-. -
According to the water analogy of electricity, transistor leakage is caused by holes.

Pitchfork

Thank you for the excellent advice
This is what I have come up with & it operates very well




Rob Strand

QuoteThis is what I have come up with & it operates very wel
l
Cool. 
Should the R10 (4k7) connect to pin 2?
Send:     . .- .-. - .... / - --- / --. --- .-. -
According to the water analogy of electricity, transistor leakage is caused by holes.

iainpunk

i know that its kinda off topic but the thread title annoys me a little

its called a hex inverter because it houses 6 inverters, when using a dip8, the maximum possible inverters is 3, so it can not be a hex inverter chip it it is dip8

im sorry, my autism couldn´t let me go further without saying this
friendly reminder: all holes are positive and have negative weight, despite not being there.

cheers

Pitchfork

The initial question related to Hex Inverters but then the suggestion to use a Dual NAND gate (CD40107) which was in an 8 pin DIL pkg as an alternative solution was posted, from then onwards the subject changed to how to use this device (and I am very grateful for the advice given)