Power wiring series and parallel

Started by Buffalo Tom, November 17, 2019, 02:53:18 AM

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Buffalo Tom

Hi. I need to get 12VDC 1 amp from a G Lab PB-1 psu. There is four 9 volt 350mA outlets available. Can I use a switching regulator and wire inputs in both series and parallel like this?


duck_arse

antonis will be along to tell you about current sharing resistors, and he will also tell you that 350mA + 350mA does not equal 1000mA.

also, your bottom two supplies are not wired the same as the top two. in3 (-) to in4 (+), no other connection to this node. does the G lab allow these connections?
" I will say no more "

Buffalo Tom

Quote from: duck_arse on November 17, 2019, 09:04:03 AM
antonis will be along to tell you about current sharing resistors, and he will also tell you that 350mA + 350mA does not equal 1000mA.

also, your bottom two supplies are not wired the same as the top two. in3 (-) to in4 (+), no other connection to this node. does the G lab allow these connections?

G Lab PB-1 has eight outputs and is full-galvanic separated (isolated from input and others outputs). Maximal current of each output is 0,35A under the condition of not passing 1A for each section. Im using section 1 with outputs 1+2+3+4 this should give me 1A.

In my schematic input 1 and 2 are wired is series to get 18V for the switching regulator. To get more current I'm adding two more inputs in parallel.

Input 1+2 = 350mA
Input 3 = 350mA
Input 4 = 350mA

Combined = 1050mA. But the current limitation on both the G-lab and the Switching regulator is 1A.. So Im expecting to get 12V 1A out of this.

Wrong?

Ice-9

No - it's not going to work that way. I would suggest buying a 12v DC 1-2amp PSU for the  purpose.
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duck_arse

series current is the same - so in1 at 9V 350mA + in2 9V at 350mA = 18V at 350mA. now you have 18V, you can't add 9V to it in parallel. in3 at 9V 350mA // in4 at 9v 350mA gives 9V at 700mA.

from that supply you can have 18V at 700mA, or 9V at 1.4A. in theory.
" I will say no more "

Buffalo Tom

Quote from: duck_arse on November 17, 2019, 11:09:58 AM
series current is the same - so in1 at 9V 350mA + in2 9V at 350mA = 18V at 350mA. now you have 18V, you can't add 9V to it in parallel. in3 at 9V 350mA // in4 at 9v 350mA gives 9V at 700mA.

from that supply you can have 18V at 700mA, or 9V at 1.4A. in theory.

Thanks for explaining! I understand now  :) Made a new version that should give me 700mA. And it might be enough.. Its for powering RJM Gizmo rack + RJM LT controller.




antonis

Quote from: duck_arse on November 17, 2019, 09:04:03 AM
antonis will be along to tell you about current sharing resistors

You didn't shout enough, Stephen, so I'm a little bit late.. :icon_redface:

Tom, depending on your power supply design, you might need a couple of "balast" resistors for current sharing between INs 1 & 3..
In your case (6V difference between regulator In & Out ) it should be more than OK to "waste" 1V , or so, for current draw equalization..
(2 X 2.7R, 400mW resistors should be marginally OK, 600mW should be more than OK..)
I'm not aware of TSR 1-24120 switching regulator specs but, in case of it could work with even lower IN - OUT voltage difference, it should be a good idea to raise resistors values (toghether, if needed, with their wattage) to let regulator run cooler..
"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

duck_arse

!  !   A  N  T  O  N  I  S    !  !
" I will say no more "

thetragichero

i understand wanting to pseudo diy but it seems like a lot of work when 1. it's likely you already have a suitable supply (maybe minus supply noise filtering) wherever you keep unused electronics  and/or 2. a 12v 1 or 2a switching supply costs less than a cup of coffee on ebay. heck, for less than the cost of the switching regulator you mentioned i got a 24v 5a supply delivered to my door about a month after ordering