Orange Squeezer problem

Started by macombaland, July 18, 2008, 10:42:28 PM

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macombaland

1.Name of the project: Orange Squeezer (OSQ), from Tonepad
2.Source of the circuit: http://www.tonepad.com/getFile.asp?id=88
3.Any modifications to the circuit? Nope
4.Any parts substitutions? 4.1M for the 4.7M resistor
5.Positive ground to negative ground conversion? Nope
6.What does it do, not do, and sound like? No sound coming from output.
7.What is the out of circuit battery voltage? =>9.3V
   Voltage at the circuit board end of the red battery lead =9.3V
   Voltage at the circuit board end of the black battery lead =0V
   
   Q1             
   G=7.9V
   S=8V
   D=8V

   Q2             
   G=1.27V             
   S=9.25V
   D=0V

   IC
   P1=0V   
   P2=0V
   P3=0V
   P4=0V
   
   P5=9.25V       
   P6=5.3V
   P7=5.2V
   P8=9.24V

   D1             
   A=0V
   K=0V

R.G.

Multiple problems:
Q1, Q2 voltages indicate soldering or pinout/orientation issues. Download the datasheet for the manufacturer of the part you used and check pinout, then check for solder shorts, or open solder joints. Example: Q2 source and Q1 gate are connected on the schematic, but show different voltages. This means they cannot, in fact, be connected on the PCB.

IC P5 shows 9.5V and P5, P7 show 5.2V. This is impossible for a properly working/connected opamp. It could be an error in measuring, or there could be a problem with the connections to pin5.
R.G.

In response to the questions in the forum - PCB Layout for Musical Effects is available from The Book Patch. Search "PCB Layout" and it ought to appear.

macombaland


macombaland

   Q1             
   G=0V
   S=9.45V
   D=1.28V

   Q2             
   G=9.45V             
   S=9.45V
   D=9.45V

   IC
   P1=0V   
   P2=0V
   P3=0V
   P4=0V
   
   P5=9.25V       
   P6=1.2V
   P7=1.2V
   P8=9.24V

   D1             
   A=0V
   K=0V

macombaland


macombaland

#5
ok I cannot figure this out..  Can someone check this out for a newb mistake??



the gap on the right side is where the diode should be.  It is on the other side at the moment.

roknjohn

Maconbaland,

Looks to me like you have 2.4k resistor where you should have a 390k resistor. This is most likely why you have 9V on pin 5 of the IC, instead of something around 4.5V.

Replace that resistor. Hopefully that will get ya going.

Roknjohn