Does dead IC act as a resistor?

[Drake120]

Well, my question is connected with debugging of my Small Stone, but I think it can help someone and it's definitely not only about the SS.

So - after some measurements, probing etc. etc., I came to a conclusion that the voltage divider produces wrong Vbias, and there must be a short between some resistor and ground. But I didn't find any. And then I measured resistance between non-inverting input (Vbias goes there) and V- (ground) of one of the IC's. 780 ohms. Is it normal? I didn't use sockets (I was lame), so the IC can be dead. It now acts as another resistor from Vbias to ground, which means that it reduces Vbias, right?

To keep this long story short, I want to ask if it's normal that the IC has a resistance of around 800 ohms between +input and V-. Or is it just 'caused by its death?

(JD)^S

[Paul Perry (Frostwave)]

An IC might have any sort of resistance, from a dead short, to totally open, between any given pair of legs, whether blown or not.
I can say this though - on a blown IC, at least some of these measurements will differ, from a 'good' one.

[Steben]

If an IC is still in the circuit (connected to the lot) you might be measuring something else that lies between those pins.

[Drake120]

True. I took the ICs away and it's still the same... I had been to stupid to think that there might be sth else that provides the resistance between Vbias and ground

Thanks for your input
(JD)^S