Simulating a reverse log pot using a linear pot

[Heemis]

I built a run off groove EA tremolo a long time ago, back before I really understood many of the details I now understand about component values.  I recently opened the unit back up, and replaced all of the components I had fudged the first time with their proper values, and it's working much better!  The one thing I forgot to replace was the 100k Reverse Log rate pot, which at the moment is simply a 100k linear pot.  I became interested in trying to simulate the reverse log taper while reading R.G.'s "The Secret Life of Pots" ( http://www.geofex.com/article_folders/potsecrets/potscret.htm ). 

I'm a little fuzzy on if I will be able to do it in this scenario, and I'm wondering if anyone has a bit of guidance to offer.  I am assuming that I am going to be using the series resistance setup on the "Pots" page, and I should be using about a 20k resistor as the parallel resistor to the pot for the most exaggerated reverse log taper.  If anyone can offer any insight, I would certainly appreciate it!

Here's a link to the EA Tremolo schematic for reference:  http://www.runoffgroove.com/EAtremolo.png

[zyxwyvu]

Here's a thread in which I made some graphs that might help you: http://www.diystompboxes.com/smfforum/index.php?topic=70732.0.

In order to get a 100k reverse log pot (assuming a 20% parallel resistor), you'll need a 500k linear pot, and a 100k resistor, approximately. You can make it more or less logarithmic by changing the 100k resistor, but it also changes the maximum resistance.

[Heemis]

Thanks!  Lots of great information in that thread!