How to choose pots?

Started by kristoffereide, March 28, 2009, 05:40:06 PM

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kristoffereide

When cooking my own effects, how do I choose which resistance pots to use?
And what would happen if I use a 10k instead of a 25k or 50k pot?
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek:

punkin

For me...when breadboarding and experimenting...I use wide range pots...big numbers. Later, after the circuit is finalized, I look at the "useable range" and get something that fits. After the circuit is finalized, I put an ohm meter across the pot and sweep the "useable range and order something close".
Ernie Ball Music Man - JPM, THD Univalve, Grace Big Daddy, PepperShredder, BSIAB2, FireFly Amplifier.

kristoffereide

ok thanks! So what happens if I replace a pot with another of less ohms is I narrow the field of tuning?
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek:

punkin

Well...the idea is to select a pot that provides a useable range to the effect. If you use something too wide, only a narrow range in the middle may be pleasing. The upper and or lower range useless. Suppose a tone pot...when you get down low to the bottom of the useable/audible range, nothing is gained but the pot may continue to turn. That's about it I think. From a user standpoint, you want a pot that has affect on the control from the left to the right of the pot...not just a little narrow range in the middle. Again, for breadboarding and testing I have several wide range pots. When I know what's useable, I order accordingly for the final circuit.
Ernie Ball Music Man - JPM, THD Univalve, Grace Big Daddy, PepperShredder, BSIAB2, FireFly Amplifier.

kristoffereide

again good sir, thanks.

But in the replacement-issue, I thought about replacing a pot in an already existing circuit.
I have about a billion 100k and 10k, but this circuit requires a 50k and a 25k.
Will I only be able to tune (100k) only on a small range on the pot, or (10k) only on a small range of the tone etc?

Can I in any way insert a resistor to a pot-leg and change the pot-value? 
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek:

ollie

Put the resistor in parallel with the pot i.e. solder them between the lugs that are connected to the circuit. When in parallel, the overall resistance is always smaller than the smallest resistor.
The duty of youth is to challenge corruption.

kristoffereide

awesome! thank you for all the answers guys!
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek:

MohiZ

#7
I'm going to paste the same links I posted in an earlier topic about a similar issue.

This article is very informative and well written:
http://gaussmarkov.net/wordpress/parts/resistors/resistors-6-mods/

This calculator will be a handy help for you:
http://www.diystompboxes.com/analogalchemy/emh/emh.html (choose linear pot or tapered pot from the menu)

I just breadboarded an IC into my heel by accidentially stepping on one  :icon_sad: ouch

kristoffereide

Thank you so much! Good reading! Sorry about your heel man, I soldered my ass the other day... and my beloved chair, at the same time! The cable to the soldering iron, should be rubber and not plastic. It has to much material memory... Fell on my chair while I was reaching for some part on a shelf.. ouch
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek:

Solidhex

Yo

  You should make note that when using a pot at the end of a circuit as a volume control the value of the pot interacts with your output capacitor and creates a high pass filter. Choosing a lower value pot in this position will make for a brighter sound.

--Brad

kristoffereide

yes, I read this in the gaussmarkov article.

Thanks though
Quote from: biggy boy on April 12, 2009, 06:22:33 PM
I find it funny how I can have close to 1000 components, yet I never seem to have enough parts to make a project. :icon_eek: