Noob question regarding a vero layout

Started by shiner_man, January 12, 2011, 05:51:09 PM

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shiner_man

I'm working off the image below and I'm fairly sure that the 2.2K resistor is the resistor for the LED so that full voltage is running to it.  Am I correct in this?

If I was to replace that 2.2K resistor with a 1K it wouldn't have any effect on the circuit right?


skrunk

that's right, the led will just be a tad brighter.
but it's there so that full voltage isn't going to it, otherwise it would burn out.

PRR

If you don't have a 2K, here you can probably run 5K or 10K, something like that.

1K will work but may be very bright, and also far more power (battery drain) than all the rest of the circuit. 4.7K is often fine on stage.
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fxseth

Because the diode is a junction device, there is no real internal resistance that will limit the current.  So if you plug a 9V battery into 0Ohm, you get a burnt out LED.  Adding the resistor limits the current through the diode which determines how bright it is.

You could use anything between 200Ohms and however high you want to go to keep it bright enough, maybe 10k, not sure.  The lower resistance will drain you battery faster.

Since you are using a perf board, why not just solder two 1kOHm resistors in series to get your 2k.