Help with klone and 2PDT wiring

[aBunchOfPedals]

Hello,

I want to build this klone:  tagboardeffects.blogspot.com/2014/07/klon-centaur-silver-edition.html

I'm a little confused about the 2PDT switch.  All of the pins are labeled on the board but I don't know what to do with the input and output on the board.  Can someone give me a hand?  Thanks!

[antonis]

I'm a little confused about your query.. 

As far as I can see, Input is connected to column 1 / row 7 (Green wire) and Output to column 1 / row 23 (Blue wire)..

If you worry about the "free" ends of In & Out wires, they're connected to respective In & Out jack lugs..

It uses a DPDT On-Bypass switch with LED indicator, so it only toggles between effect and bypass Outputs..
(SW4/5/6 is the S1A and SW1/2/3 is the S1B on respective schematic..)

[slashandburn]

*deleted*

Not sure what I'm talking about. It was wrong , anyway! Sorry

[antonis]

@ Iain: I've though the same at first but if you look at that specific layout (and at accompanying circuit schematic) the DPDT switch is for On-Bypass purpose..!! 

(there are some other versions of Klone Centaur, like Rev. 2, using an additional DPDT switch for selection between soft and fat clipping modes with also a DPDT switch for On-BYpass mode..)

[slashandburn]

Looking closer, you only need the one switch.  I think your in and out from the board go straight to their respective Jack socket lugs!

Edit: yeah disregard my first post entirely. It's a buffered bypass, no second switch.

[antonis]

Closer looking has always better results.. 

[aBunchOfPedals]

I'm a little confused about your query.. 

As far as I can see, Input is connected to column 1 / row 7 (Green wire) and Output to column 1 / row 23 (Blue wire)..

If you worry about the "free" ends of In & Out wires, they're connected to respective In & Out jack lugs..

It uses a DPDT On-Bypass switch with LED indicator, so it only toggles between effect and bypass Outputs..
(SW4/5/6 is the S1A and SW1/2/3 is the S1B on respective schematic..)

Ahhh, ok.  So the input and output of the circuit are actually connected directly to the sleeve lug of the 1/4" jacks? 

[antonis]

Ahhh, yes..!! 
(but I should propose you to connect them to the tip lugs or you'll have a VERY QUIET pedal..)

(in any, case you can't damage anything..) 

[aBunchOfPedals]

Ahhh, yes..!! 
(but I should propose you to connect them to the tip lugs or you'll have a VERY QUIET pedal..)

(in any, case you can't damage anything..) 

Duh!  Of course, my bad.  The neutral goes to the sleeve.  Thanks man!  Working on it now!