Blueshift chorus stereo, how should it work?

Started by matopotato, August 25, 2024, 01:35:08 PM

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matopotato

A few weeks back I wanted to test a few pedals in stereo, one of them being the Blueshift Chorus by Aion FX.
As per the documentation:

QuoteStereo operation
The DC-2 was designed to accept a mono input and split it into stereo, with one BBD controlling each side of
the stereo signal. However, the unit can also mix the signal back down to mono if you are not running a stereo
configuration.
If you have a cable plugged into output "B", the signal will be split into stereo between "A" and "B". If nothing is plugged into output "B", the signal will be summed to mono.

If I connect one output to only one amp it sounds as if the base output (A) is chorusing fine, but the B output give much less chorus compared with A, but there is chorus in B as well.
If I connect A to amp and take B in and out, I hear nothing different in A. I would have expected A output to change with B in or out since A should give the sum when B is empty.
Also I thought B would have sounded similarly as much chorusy as A does.
Any thoughts if something is wrong or if this is expected behavior?

Here is an earlier post about the building with issues I faced then until I got it sorted. (At least I thought so)

Thanks
"Should have breadboarded it first"

aion

A and B should both sound pretty much exactly the same, the chorus modulation is just inverted (i.e. when one side is high the other is low). Unplugging B should definitely change the sound in A, but only if you unplug it from the effect side, not the amp side, since the switching jack controls a JFET switch inside the effect.

I would check the voltage on Q3's gate (D5 anode) and see whether it changes when a jack is plugged in vs. out. If the jack's ring connection isn't wired up correctly then the stereo/mono switching won't work right.

matopotato

"Should have breadboarded it first"

matopotato

#3
Ok, A and B with a cable in each: Q3 Gate reads about 0mV, Source 4.5V and Drain about 4.3V
Pulling out B:
G 70mV (or a bit less), S and G both around 4.5V
So it changes, but not sure 70mV is enough to be a change...

EDIT: No signal passed through, just plugged it in to the chain and powered it up.
"Should have breadboarded it first"

Mark Hammer

Quote from: aion on August 26, 2024, 10:00:22 AMA and B should both sound pretty much exactly the same, the chorus modulation is just inverted (i.e. when one side is high the other is low). Unplugging B should definitely change the sound in A, but only if you unplug it from the effect side, not the amp side, since the switching jack controls a JFET switch inside the effect.
Yes and no.  If the difference between the two outputs is that one is sum (dry+wet) and the other difference (dry-wet), then the second one will be lower in perceived amplitude because of the cancellations.  If one has a phaser, flanger, or chorus that provides this sort of "stereo", you'll note this difference in loudness.

In the case of the DC-2, however, the two outputs are electronically in phase.  IT is only their LFOs that are phase-reversed, to provide countersweeping.  So there shouldn't be any wholesale difference in loudness.  Now, were one to somehow "freeze" the sweep, I would imagine that there would be points in the sweep cycle where the one side could sound quieter than the other side, simply because of where the notches are being produced.  BUt that wouldn't apply to the DC-2.

matopotato

Quote from: Mark Hammer on August 26, 2024, 03:32:28 PM
Quote from: aion on August 26, 2024, 10:00:22 AMA and B should both sound pretty much exactly the same, the chorus modulation is just inverted (i.e. when one side is high the other is low). Unplugging B should definitely change the sound in A, but only if you unplug it from the effect side, not the amp side, since the switching jack controls a JFET switch inside the effect.
Yes and no.  If the difference between the two outputs is that one is sum (dry+wet) and the other difference (dry-wet), then the second one will be lower in perceived amplitude because of the cancellations.  If one has a phaser, flanger, or chorus that provides this sort of "stereo", you'll note this difference in loudness.

In the case of the DC-2, however, the two outputs are electronically in phase.  IT is only their LFOs that are phase-reversed, to provide countersweeping.  So there shouldn't be any wholesale difference in loudness.  Now, were one to somehow "freeze" the sweep, I would imagine that there would be points in the sweep cycle where the one side could sound quieter than the other side, simply because of where the notches are being produced.  BUt that wouldn't apply to the DC-2.
Thanks!
I could try with scope next I guess.
Verified with a TRS jack (male) that A and B wiring is correct.
"Should have breadboarded it first"

matopotato

Sorry for taking so long in coming back on this.
I tested a bit today with a tone generator and a scope.
My perception is that the signal gets a little bit amplified coming out from jack A. It is wobbling and the switches have visual effect.
Jack B is same as input in amplitude, or slightly less. So there is a difference between A and B.
B also reacts in a similar way to the switches.
So I would say that the signal has different amplitudes on A and B.
But I did not use a TRS cable on B, just a mono one.
Not sure if I should have tried with a TRS in B instead, but then what would the other end be? (Intended to go to an amp anyway, so should be mono?)
Or is the TRS jack B a switching jack that will keep B out of the equation until a jack is inserted?
"Should have breadboarded it first"

bluebunny

Quote from: matopotato on December 15, 2024, 07:25:37 AMOr is the TRS jack B a switching jack that will keep B out of the equation until a jack is inserted?

All jacks are intended to be mono.

Quote from: aionIf you have a cable plugged into output "B", the signal will be split into stereo between "A" and "B". If nothing is plugged into output "B", the signal will be summed to mono.
  • SUPPORTER
Ohm's Law - much like Coles Law, but with less cabbage...

matopotato

Quote from: bluebunny on December 16, 2024, 08:01:08 AM
Quote from: matopotato on December 15, 2024, 07:25:37 AMOr is the TRS jack B a switching jack that will keep B out of the equation until a jack is inserted?

All jacks are intended to be mono.

Quote from: aionIf you have a cable plugged into output "B", the signal will be split into stereo between "A" and "B". If nothing is plugged into output "B", the signal will be summed to mono.


Thanks for clearing.
Then I would say my test ended in lower output in B.
And I am not sure if my previous measurements on Q3 (post #3) make sense or not. (And if not, then what might be the cause)
 
"Should have breadboarded it first"

matopotato

I try to measure Q3 again and power up with 9V.

                            A&B    A       B
Drain  (to R90)    4.46   4.6     4.43
Source (to R91)    4.5    4.67    4.45
Gate   (to D5)    -0.24   0.058  -0.25

I also tested continuity.
From the point M where the Ring comes in, there is continuity to R2 and R1 as it should
Cable in B, and the sleeve/ring connects to M.
Here I have been a little bit confused looking at the schematic. With a mono jack in B, the Ring and Sleeve connect? Effectively shorting Ring to ground. So the TRS in B is mainly to act as a switch I guess.
Please correct me if I misunderstood this.
Also would appreciate if anyone can say if the readings above indicate expected values or not.
The Drain and Source especially Source kept falling, had to take a reading when it had sort of slowed down.
(Link to doc in first post)
"Should have breadboarded it first"