a pull down resistor and a polarised cap question

[yeeshkul]

Let's say  i have a polarised cap at the input of my circuit and want to add a pull down resistor down for obvious reasons.

The cap is oriented like: (+) towards the input jack
                                       (-) towards the pnp tranny (ground is +).

When i want to place a pull down to help the tranny discharge do i have to place the pull down so it connects
(+) cap side and (-) battery pole OR
(-) cap side and the ground ?

[R.G.]

Let's see if we can reason this out.

The "obvious reason" is to keep capacitor leakage from changing the voltage across the capacitor if it's open circuited by the switching arrangement. Since guitars can't put out DC, its signal must have a DC level of 0V - that is, ground.

In this pedal, ground is connected to the - side of the battery, which is completely irrelevant to the question at hand.

In every pulldown resistor situation, the resistor goes from the outboard end of the capacitor to ground - whatever that ground is - because when you reconnect the cap, you want its outside end to be at ground, just like the guitar signal is.

So in your case, you want the resistor from the + cap side to ground.

I'm confused by your comment "help the tranny discharge". You don't want to do that. You want all the DC levels to stay exactly the same whether you have the effect switched in or out. Otherwise you get pops.

[yeeshkul]

R.G. thank you for your patience. 

I seriously thought, that the pull down resistor drags down the voltage that stacks on the cap when the cap is cut off by DPDT switch. I thought that the pop is caused by the cap current when the cap discharges itself once connected back. I just did not know anything about the capacitor leakage. Thank you kindly for the reply.

[yeeshkul]

So if i understand well now, the "pop" is caused by the cap that is being recharged back to the working voltage?

This is how i understand the occurrence now (i am talking just about an input cap for simplicity):
At the moment we cut the circuit off by DPDT the cap loses some of its voltage due to the leakage current that drags the DC voltage down to the input terminal point. So the cap is not fully charged and cannot recharge because the circuit is open.
When we connect the guitar again - we enclose the circuit and cap charges itself from the battery again which causes the pop.

I am right now?  

[gaussmarkov]

So if i understand well now, the "pop" is caused by the cap that is being recharged back to the working voltage?

This is how i understand the occurrence now (i am talking just about an input cap for simplicity):
At the moment we cut the circuit off by DPDT the cap loses some of its voltage due to the leakage current through the cap that drags the DC voltage down to the input terminal point. So the cap is no fully charged and cannot recharge because the circuit is open.
When we connect the guitar again - we enclose the circuit and cap charges itself from the battery again which causes the pop.

I am right now?  

yes, i think you have it.  that is also my understanding. 

[yeeshkul]

ufff, thanks god hehehe