Will this work? (looper/switcher)

Started by kyle31, July 13, 2007, 03:01:01 AM

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kyle31

I'm trying to design a box that houses 2 effects loops that can be run separately, together, or bypassed and a/b/y switching for my amps.
While I was at it I went ahead and put my LEDs and power stuff too...

It's basically an effects loop running into an effects loop then running into an a/b/y switch.

Will this do the job?

please excuse my crappy drawing

all sleeves are grounded of course. i just forgot to draw it.....

Please help me :icon_cry:


Shot at 2007-07-12

ambulancevoice

the 1k resistors need to be inbetween the 9v+ and the LED
Open Your Mouth, Heres Your Money

MikeH

Actually the resistors can go anywhere in the path, as long as they are in series.
"Sounds like a Fab Metal to me." -DougH

MarcoMike

I'm not sure about the 9V+ going to the input jack. what about a "ground" instead?
the following A/B/Y section is well tangled... :P  but it seems it could work.
Only those who attempt the absurd will achieve the impossible.

kyle31

Thanks for the replies!!!!

I got the thing about the resistors, but should the switchpole i had the resistor on go to ground?

as for 9v+ going to the ring of the input,  thats just what i saw on an offboard wiring diagram on ggg.

all jacks will be grounded.

is there any better 'untangled' a/b/y?

thanks again

MarcoMike

Quoteas for 9v+ going to the ring of the input,  thats just what i saw on an offboard wiring diagram on ggg.

If you connect it that way, inserting the jack will short + and -, which is not really good :-\
but looking at your drawing I guess I know where the mistake is: the bigger contact on the battery is actually the negative one, so it's the one which goes to the jack's ring. just rub off the 9V+ from that wire and it's ok.

regarding your LEDs' resistors, it looks absolutely ok!
bye
Only those who attempt the absurd will achieve the impossible.