ac dc bridge question

[9 volts]

I've been experimenting with ac dc bridges as a means to use a milli amp meter to measure voltage. I've noticed that the lower the resistor I use in series, the lower the voltage reading on both sides of the bridge (ac and dc). Eg if I use a 10k resistor I get 4volts. If I use a 1k resistor I get 2 volts. Both sides of the bridge change....
see link http://www.circuitdb.com/circuits/id/191
It's like the ac is influenced by the load on the dc side.........does this make sense?
Thanks

[R.G.]

I'd like to help, but I can't figure out what circuit you mean, and how it's connected. The link is not to an AC/DC bridge. Can you post more info, perhaps a schematic?

[9 volts]

Thanks, I've been building this distortion meter

I figured I could monitor the input voltage with a milli amp meter by connecting the monitor outputs (see schematic) to a diode bridge. I then did the calculations mentioned in the above link (eg measure 50 volt into 5 milli amp eg 50/.005 = a 10k resistor). I also added a big capacitor (smooth) across the dc output. This worked. I then figured it could be good to make the resistor switchable eg 1k or 10k so I could measure 50 volts or 5 volts. I've noticed that a measurement of 4 volts via the 10k resistor will only be maybe 2.5v when I switch via the 1k resistor. When I ran over it with a multi meter I noticed that the ac and dc measurements on the diode bridge both drop when going through the 1k resistor....
It's a little away from pedals but an old meter looks good on anything and I figure this could be a good tool to refine pedals etc. The process has been a good learning curve. Thanks again
schematic:
http://www.freeinfosociety.com/electronics/schemview.php?id=330.