puzzled with stereo rev log pot

[Dimitree]

hi everyone
I bought a 100k STEREO LOG pot, because I want to use it instead of the 100K STEREO REV LOG that my schematic claims.. I know that I have to reverse the outer lugs..and then using the pot in the opposite direction..but I'm a bit puzzled about how to reverse the lug..


1a is the first lug of the upper wiper, etc..

So I have to change 1a with 3a, then 1b with 3b.. Then 2a and 2b goes to 1a and 1b or to 3a and 3b? and at the end, which lug goes to R24 and which to R25?

sorry for this, I hope my poor description doesn't puzzle too much
thanks
Dimitri

[MikeH]

I'm actually totally puzzled.  Any chance you could elaborate/clarify?

[Dimitree]

I will try 

I have to use a 100K log stereo instead of a 100K rev-log stereo used in the original pedal..
So in order to use a log instead of a rev-log, we need to invert lug 1 with lug 3, and the use the pot backwards.. This should be right, no problem here.
Now, since this is stereo (so 2 wipers), and the lug 3 of the first wiper is connected to lug 1 of the second wiper (look at the schematic posted before), I don't know how to connect the lugs in order to "fake" the rev-log pot and the configuration used on the schematic

I hope this explain.. I'm not english so sorry if it is not clear

[MikeH]

Oh- I got it.  That makes sense.  So, looking at the schematic, the whole point is to increase or decrease the amount of resistance between points labeled r24 and r26, while simultaneously increasing the resistance between r26 and r25.  We're only dealing with varying resistances, not voltage dividers.  So the only thing that we need to change here to use a regular log pot instead of a rev log pot, is how the resistance is changed, not the points that the varying resistances are connected.  Simply connect lugs 2 and 3 together, instead of 1 and 2, for both sides.  That ought to do it.

edit: Oh, you also have to physically flip the pot around in the schematic, so lug 1 goes where 3 is and vice versa.  So you're right, 3b will connect to 1a and thats where the r26 connection will be.

[Dimitree]

many thanks Mike!

so this should be the conversion, if I understand well:

you also have to physically flip the pot around in the schematic

does this mean that I have to invert the point R24 with the point R25? or all I have to do is connect 2a/b to 3a/b (in this case, the conversion schematic is wrong)?

[MikeH]

Just imagine in that schematic you take each pot individually and flip it around; to 3a goes to r24, 1a and 3b are connected and go to r26, and 1b goes to r25

[Dimitree]

fine!
many thanks!!
that should be the "final schematic"