Help with The Mole Booster

Started by Jhouse, December 30, 2010, 11:17:04 PM

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Jhouse

So let me just say that I managed to mess up a pedal on perfboard (first time trying this. I'm not sure if I like it), a booster no less. *epic face palm*

Anyway, THIS[/u] is the schematic I'm using and THE LAYOUT[/u] that I used is here. You'll have to scroll down the page a bit. I think it is called the "Hog's Foot" on there too.

My substitutions were that I used a BC549 instead of the 2n5133 in the schematic or 2n3904 called for in the layout. C1 and C2 are 4.7 uf. R1 is a 47k and R2 is actually 2 220k resistors in series. I basically built this bad boy with whatever I had off hand, just something to keep me busy for a little while and try my hand at using perfboard.

I'll just give you guys my values for everything since there are only like 10 parts involved.

Q1
C= 4.00
B= 4.89
E= 3.98

C1
+= 4.89
-=  0.00

C2
+= 4.00
-=  0.00

C3
To V+= 9.00
To C=   4.00

C4
To Ground= 0.00
To B         = 0.00

R1
To Ground= 0.00
To B         = 4.98

R2
To V+= 8.98
To B   =4.81 (This is after going through both resistors.

R3
To V+= 9.00
To C  = 4.00

R4
To Ground= 0.00
To E         = 4.01



slacker

Something is wrong with the voltage at the base of the transistor, you should have about 0.8 volts there not 4.89. Double check the connections round there.
Probably not part of the problem but the connection of C2 is wrong on the layout. The positive side is shown connected to the row with the base on, but it should be on the row above.

Jhouse

Yeah, I caught that layout mistake. So that's fine. I resoldered the parts to the base and got the same voltage and still the complete lack of sound when I turn on the pedal (bypass works fine).


PRR

Q1 Emitter or R4 voltage should be like 0.25V, NOT 4V.

Even then it dos not make sense.

Remove transisor. The "B" hole should be (for 440K+47K) very near 0.87V. The "E" hole should be zero. When checked with ohm meter, several hundred ohms to ground (not K-ohms!). "C" hole should be pulled up to 8.999V.

Short between "C" hole and "E" hole. The voltage on this shorting jumper should be 0.34V.

If all that is right...... get another transisor, generic Silicon NPN, and check the pinout.
  • SUPPORTER

Jhouse

Well, I popped out the transistor. These are the values that are got for the aforementioned "holes."

E = 0.00 (:D)
B = 8.99
C = 7.98

PRR

> the values that are got
> B = 8.99


The 470K+43K (or 440K+47K) voltage-divider should set this point very near one-tenth of the 9V supply.

The 47K may not be soldered right.

However I am wondering if your 220K+220K is maybe two 220 ohm resistors.

Read the whole help-post. I gave additional checks which you have not reported.
  • SUPPORTER

Jhouse

QuoteThese are the values that are got for the aforementioned "holes."

"Are got?" Seriously? It's hard to believe that English is my first language sometimes.  ;D

QuoteHowever I am wondering if your 220K+220K is maybe two 220 ohm resistors.

So I read that statement with pure skepticism. "Surely I know the difference between a 220 ohm resistor and a 220k," I thought.

I look at the bands on my resistors. Red, Red,.......BROWN!?!??! Yeah. I don't even know how I made that mistake.

In short, after putting the right resistors in, the pedal works.