ChargePump from 9VDC to +15V -15V not enough current

Started by Mbas974, December 31, 2011, 03:45:05 PM

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Mbas974

..aaSSppp!! Don't get enough current for my circuit.  it is the SDD3000 pre only.

I built a charge pump dual supply +15v and -15v from 9v with LT1054.
Measured as open the positive supply is 15V the negative is -15V,
when I put the supply into the circuit the + 15V become +12V and -15V become -5V... i think it is short of current.

Any suggestion ?

This guy uses only one chip having 8 pin (in the middle of the rotary switch) but I ignore what it could be...
http://trabantland.wordpress.com/category/diy-guitar-effect-pedal-projects/sdd-3000-preamp-clone/

Thanks in advance.

iccaros

can you post the schematic you used and or pictures of what your trying. I think I get what you are connecting to, but how you made your charge pump?

Keppy

I had a similar problem once. You might get enough current using two doublers, one positive and one negative. You could also use a 15v supply and just do one inverter, but it'd have to be regulated because that's the maximum recommended input for that IC.
"Electrons go where I tell them to go." - wavley

Galego

I've built way more complex circuits with two 7660S to get +-18V and then used 78L15/79L15 to regulate to +-15V, worked perfectly.

Are you sure that he's using +-15V? Couldn't he just be inverting the 9V to get +-9V?

PRR

> Are you sure that he's using +-15V?

If you read the too-many-posts blog, that was one of his goals, original voltages.
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Mbas974

 A clarifications

the schemantic . is exatcly the one linked
http://analogguru.an.ohost.de/001/schematics/Korg_SDD-3000-pre.gif

this is the charge pump:
http://forum.musikding.de/cpg/displayimage.php?album=14&pos=4


Circuit anyway works, sound is great !
But when measuring the positive supply is 15V the negative is -15V (only the charge pump no connected to the circuit), when I put the supply into the circuit the +15V become +12V and -15V become -5V...
I was expecting that +15V and -15V did not change...powering the circuit.  Am I wrong, or this is normal ?

Mbas974

GOOOOOD NEWS !!!

I've SOLVED NOW using a diode to connecting ground of the circuit.
For some reason that I'm not able to explain grounding the circuit with normal wire with the power's ground
it's reduce the supply, putting a diode as connection (1N5819 in my case) there is no loss of voltage in supply .


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