Misbehavin' Big Muff voltages.

Started by VPIF, February 22, 2013, 01:41:54 PM

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VPIF

Hi.

I'm trying to figure this one out, but I'm kinda' stuck. Looks like Q2 is shorted to ground, but I don't get continuity with the meter... Any help will be appreciated.

1.What does it do, not do, and sound like?= Low gain, low volume, scratchy tone pot.
2.Name of the circuit = GGG big Muff – Civil War version.
3.Source of the circuit (URL of schematic or project) = http://www.generalguitargadgets.com/pdf/ggg_bmp_rusc_sc.pdf
4.Any modifications to the circuit?= No
5.Any parts substitutions? = No.  Used 2N5089 transistors.
6.Positive ground to negative ground conversion? No
7. Battery voltage? = 9,01
Voltage at the circuit board end of the red battery lead = 8,89
Voltage at the circuit board end of the black battery lead = 0

Q1
C =0,13
B =0,72
E =4,45

Q2
C=0
B=0
E=8,78

Q3
C=0,12
B=0,70
E=4.29

Q4
C=0,92
B=1,40
E=5,36

D1
A=0
K=0

D2
A=0
K=0

D3
A=0,70
K=0,47

D4
A=0,70
K=0,47

Govmnt_Lacky

You list all your Emitters at higher voltages. Did you transpose the numbers wrong OR do you have all of your transistors in backwards?
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VPIF

The transistors are put in as shown on the layout diagram on the GGG website. I found a website that says it's C, B, E from left to right on the flat side of the transistor. Maybe I should pick my sources more carefully :) The circuit is producing sound, allbeit low on gain and volume, so the transistors have to be in the correct orientation, I guess.

Short answer: It's pretty likely that I transposed the numbers in the incorrect order.

LucifersTrip

Quote from: VPIF on February 22, 2013, 01:41:54 PM

Q2
C=0
B=0
E=8,78


there's really nothing more to do until you sort this out. simply scrutinize the area around that transistor and get voltages close to Q3
always think outside the box

Govmnt_Lacky

#4
Quote from: VPIF on February 22, 2013, 02:03:23 PM
I found a website that says it's C, B, E from left to right on the flat side of the transistor. Maybe I should pick my sources more carefully :)

If you are using 5088s, then you have them in backwards.

5088s are E, B, C from left to right with the flat side facing up and the leads pointed towards you.



EDIT: I see above that you are using 5089s. Should be same pinout as I diagramed above but, I would go with 5088s if you want to stay true.
A Veteran is someone who, at one point in his or her life, wrote a blank check made payable to The United States of America
for an amount of 'up to and including my life.'

VPIF

Thanks.

OK. I swapped the collector and emitter voltages, then. Got to remember which i which soon  :icon_redface:

I will examine the circuit around Q3 in detali tomorrow, and report back. Now it's bedtime on this side of the Atlantic.

Thank you for your replies, kind Sirs :)

PRR

Ass-uming transposed:

> Q2
> C E = 0
> B=0
> E C =8,78


R10 470K is not really there; suspect bad solder joint.



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VPIF

Quote from: PRR on February 23, 2013, 01:02:34 AMR10 470K is not really there; suspect bad solder joint.

WOW! I wish I can do that someday. I know it's relatively simple circuit, but that's really impressive to me. You were, of course, spot on, and I bow my head in gratidute and respect.

I would like to thank everyone who contributed, before I go and bask in creamy muffiness :)

PRR

R10 pulls the Base up. Base is not up. Therefore R10 isn't doing its job. Since resistors rarely fail (without smoke), joints are first-suspects.
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