need to find a stacked pot....

[antonis]

i'm guessing you could use two 47k instead of 200k if ya need a 100k source impedance maybe

I beg your pardon..??
(are we talking about the above BJT buffer or did I miss something..??)

I thought that the input impedance of an emitter follower stage was the equivalent input biasing resistor in parallel with the input impedance of the emitter follower (which is the current gain times the emitter resistor)..

As I wrote above, we've got 2 biasing resistors effectively connected in parallel (for a VERY LOW source internal resistance) which give us a total resistance of 110k..
This resistance (110k) is connected also in parallel with the 3k3 emitter's resistance times the transistor's gain...
(I ommited the transistor's internal b-e resistance for simplicity but we can easily calculate it from Rbe=25mV/Ie)


P.S.
Or maybe I'm totally out of what we are talking..

[wolfy]

Thanks again, I have the pedal now, and will let you know how I go - few things a miss here and there!