Feedback Looper Always On, wiring help needed!

[rudeez]

Hey!

Currently working on a feedback looper, somthing like this http://experimentalistsanonymous.com/diy/Schematics/Buffers%20Switchers%20Mixers%20and%20Routers/Feedback%20loop.gif
I'm putting this togheter with a chorus in a BB size box. I have one problem tho, i can't figure the wiring out.
What i want is to have the whole pedalboard in the looper chain meaning that i dont wanna use send/return jacks, i want the internal wiring to be so that everything on the board is included.
Is this possible by any chance? I'm using a DPDT as i dont need LED indication for it.

[jblack547]

Definitely need more info. A gut shot would help. Do you mean to not have the send and return on the outside of the box?

[rudeez]

Theres no gots right now really, i'll wire the chorus part as per regular true bypass, from that i get the out lug which should go to the output jack but now i want this feedback looper after the chorus.
Erm, as i said i just want the whole pedalchain to be in the feedback loop witout using an external loop for it. By that i mean plugging the pedal in like one normally would you also have a feedback switch that will include all the pedals of the chain.

[jblack547]

Is the chorus the only pedal in the chain. Im missing something.

[rudeez]

Nah, the chorus will just be in the same box, other then that imagine having a regular pedalboard with a few delsay, verbs, od's and such.

[jblack547]

Just found this over at EA. Nice article.

http://experimentalistsanonymous.com/board/index.php?topic=134

Do you mean to just have the chorus in the feedback loop? And, you want it all in the same box?

[jblack547]

--> whole pedalboard in the looper chain meaning that i dont wanna use send/return jacks

guitar -> looper/chorus -> amp

Where would the rest off the pedals go?

[Quackzed]

ok... you plug guitar into the (chorus/looper box)--- this is the chorus input(true bypass inside this box)---then from chorus output(Truebypass) Directly to the looper input(same box -no jack here)... ok...
now we're at the looper input. how can you connect anything to the loop without jacks? you need a send and return for the pedalboard.
you cant fit the pedalboard 'inside' the ch/loop box. you need send and return jacks. just like you need an input and output jacks on it.

       --fx1in--2-3-fxlast out--
       \                              /  
        ----[send  ret]--------
guit in----[ch/looper]----out to amp
             [ o        o ]
           chTB    loop tb  (switches)
without the send return jacks how can you go into and out of the pedalboard?

[ashcat_lt]

You need two connections to both the input and output of the chain in the loop in order to make feedback.  One input comes from whatever is before the feedback loop.  One output goes to whatever comes after the loop.  The other output feeds the signal back to the other input.  Without that, there's no loop, and no feedback.

Edit - You don't need the switch to turn the feedback on or off if you know you always want it on.  You will want the pot to adjust the amount of feedback.  Even with the pot, it's very tough sometimes to dial these things in for anything useful or more interesting than a ringing tone.  On mine, I opened up the pot and cut the track at the end so that when I turn the feedback pot all the way down (actually, maximum resistance) it disconnects the path - essentially combining the action of the switch in with the pot.