Question on Schematic substitution

[olewaylon]

http://www.generalguitargadgets.com/pdf/ggg_sw_aby3lg_instruct.pdf

In this schematic it calls for two 1k resistors to be twisted together.  Im wondering if I could just use one 2k resistor in it place.  thanks

[Pojo]

No, it needs 2 1k resistors. Take a look at the schematic here: http://www.generalguitargadgets.com/pdf/ggg_sw_aby3l_sc.pdf

The tied together end goes to ground and each resistor goes on it's own path to limit the current on the leds that are switched on. On a side note, you can try subbing different values depending on the desired brightness. 1k on the common super bright leds is BRIGHT! Raising the value will tame that and save battery at the same time.

[mth5044]

I don't see why you couldn't use a different value resistor from 9V to the anodes and only use one.

[olewaylon]

I plan on using DC power only.  I have 2K resistors now.  Its easy enough to pick some 1K up at RadioShack.  Will it make much of a difference?

[PRR]

Use two 2K resistors.

It won't be as bright; but newer LEDs tend to be brighter anyway. Values of 5K and 10K often work fine.

[mth5044]

What he says ^

If they are the diffused type, they will typically be quite bright enough with 2k.

If they are the clear type, you'll probably scorch a retina. I use 12k-27k for those.

[antonis]

You can always use 2 X 2k resistors as a parallel pair but, as Paul said, 7mA is an overkill for modern LEDs...

[Cozybuilder]

I like blue for on/off, and use 47K with the 3mm LED- thats plenty bright.

[olewaylon]

Thank you for the help.