Calculate high power led resistor

Started by Yesing, May 25, 2023, 05:59:30 AM

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Yesing

Hi!
How do I calculate the resistor to be used with the following high power leds?

-3W: 3.2 - 3.4V // 500 - 700mA
-5W: 6 - 7V // 700mA
Is it good practice to use resistors for these leds or should I used an led driver? I wanna post this issue in FAQ topic but it locked.

thanks!

GibsonGM

#1
Hi and welcome!

The formula to find an LED dropping resistor's value is:  Supply voltage (Vs) - LED forward voltage (Vf) /  LED current in mA  = resistance

so  Vs-Vf / Iled = R

As long as you are not trying to dissipate more power than the resistor can handle, whether you use a driver or not depends on the application (basically, it's up to you to choose).  You can calculate the power used by the circuit and choose a resistor that is higher rated than the work you are doing with it...

If you describe or show the project you're using these in, others may have more advanced suggestions for you!  :)
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antonis

Hi & Welcome..

Obviously, we don't deal with +9V (or even +18V) powered effect.. :icon_wink:
(unless we wish to illuminate the whole gig stage..)

I don't get your Power/Voltage drop/Current correlation (supposing 3W & 5W are refered on LEDs power..)

As Sir Mike  sais above, the power to be dissipated depends on Power supply voltage, LED forward voltage drop and current through it and is non-negotiable..
e.g. supposing you have to dissipate X Watts.. They can dissipated as a wholeness (at one item/device) or partially (at a combination of series items/devices).
(those items can be resistors, transistors, relays or any combination of them..)
"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

duck_arse

" I will say no more "

antonis

"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

duck_arse

homepage spamm link removed. post and thread would have followed, except someone's posted to.
" I will say no more "

GibsonGM

That first post always gets me, and such good questions, too!  :) 
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antonis

Quote from: GibsonGM on May 25, 2023, 06:06:44 AM
Supply voltage (Vs) - LED forward voltage (Vf) /  LED current in mA  = resistance

In kilo-ohms, I'd dare to add, your Highness.. :icon_wink:
"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

GibsonGM

Good eye, Adonis...everything is in amperes and ohms unless specified, and I did specify mA...
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antonis

To be honest, kudos should go to Stephen..  :icon_redface:



"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

GibsonGM

I'm not a mathlete (I suck at math and forget where I convert or not, more in writing than in practice).  When I see the number on the calculator, I mentally convert it then and there if needed.  Don't ask me how it works, but it does (for me).   I play guitar far better than I do math :) 
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MrStab

No, no, no. It's a biological equation. You must find the median between where most users experience retinal damage, and where they complain about dimness.
Recovered guitar player.
Electronics manufacturer.

Jarno

Better way would be to use a constant current driver, right? Not so much for those few mA of a red led on an effects pedal, but for maximum efficiency in retina burning high power LEDs

This came to mind (retina burning) :)

MrStab

Perhaps, if efficiency were the key parameter, and PCB space and cost were lesser considerations.
Recovered guitar player.
Electronics manufacturer.