Ross Compress Switch Mod Question

[modsquad]

I have made the switch the following way:

1.  Soldered 39k resistor across pole 1 and 3
2.  Soldered together 10k and 150k resistor leaving the lead on the 150k at the join extended, soldered it to the middle pole.
3.  Soldered lead of 10k to pole 1.

My questions are 1) Is this correct? and if it is 2) Where and how on the Vero do I solder the switch connections?  I used the following layout to put together the circuit:

http://aronnelson.com/gallery/Toneys-Album/Rossv4

Thanks,

Stan

[modsquad]

Bump

[Mark Hammer]

The centre lug of the toggle can connect to either of the side lugs.  Since you want the resistance to be either the full 150k+10k, (slowest recovery, hence longest sustain), the shortest possible resistance (10k = fastest recovery), or something in between (10k+ [150k and 33k in parallel] ) = 37k, you need to either have nothing in parallel with the 150k (for max resistance), a straight wire in parallel (for min resistance), or a second resistor in parallel (for medium resistance).

So...connect the centre lug of the toggle to the junction between the 10k and 150k resistors.  One of the side lugs of the toggle goes to the other side of the 150k resistor.  The other side lug has a 33k resistor soldered to it and secured to the toggle with some heat shrink to make sure it doesn't fracture easily.  The free end of the 33k resistor also goes to the other end of the 150k resistor.  Now, in the middle toggle position, there is no connection to the other end of the 150k resistor.  One side connects a straight wire, and the other side position connects the 33k resistor.

Done.

[modsquad]

Okay so it looks like I soldered it corretly.  Now based on the Veroboard layout there is a SWP and SW identified.  I assume this is where the switch is wired into the circuit.  I am confused on how to do it (what is SW and SWP).

Stan

[bancika]

SW goes to center lug of switch and SWP goes to outer lug, doesn't really matter which one. At least I did it that way

[modsquad]

I am confused on what is connected to the lug of the 10k resistor that is "hanging out there" after connecting to the 150k.  Am I just being dense about this?

Stan

[bancika]

It goes like this:
1st position: 39K is put in parallel with 150K giving 30K + 10K in series = 40K
2nd position (off), nothing is connected in parallel so we have 150K + 10K = 160K
3rd position: bypassed 150K resistor giving only 10K
Any clearer?