DC Jack and 3dpt

[rasco22862]

Hi, i´m kind of new building this pedals. I´m starting with the Marshall BluesBraker from this page:

http://www.generalguitargadgets.com/index.php?option=content&task=view&id=32&Itemid=60

1)Fist of all i have a doubt, because the circuit got a dc jack and a 9v battery, so it´s possible to have 2 power source in a circuit?
2)if the answer for the first question is "YES" , what are the pros and how they work?
3)what voltage should be the dc jack?
4)what is the voltage for the general circuit?
5)i get a switch that has 2 positions, and nine little "outputs". it´s a little bigger than the de 3dpt. is this the same, can i use this swith?

Thanks and sorry my English.

[Seljer]

1,2) yes, most DC jacks allow you to have it wired up, so when have something plugged in the connection for the battery is broken and only the power from the jack is beingused

3) well 9V DC, but the jack commonly used for other guitars pedals is usually listed as "2.1mm power jack" in catalogs

4) roughly 9V DC

5) maybe, we need some more details on your switch

[rasco22862]

its a simple switch with 2 positions. on one position:

-Connected       -Connected      -Connected


-Connected       -Connected      -Connected


-Disconnected    -Disconnected   -Disconnected

And on the other position:


-Disconnected    -Disconnected   -Disconnected


-Connected       -Connected      -Connected


-Connected       -Connected      -Connected

Also the swith says 220v. is this matters?

[Seljer]

that sounds like a 3DPT switch to me yep, you can use it (the sections are only connecting in ther vertical columns right?)

[rasco22862]

Yes, vertical.Thanks i had two another questions: 

1)how is the wiring if i only use the 9v battery?

this is the original:



2)i´m using a mono jack for the input, but the mono jack has three "rings" (connectors). Using the tester, i realized that one if for the tip, the other is for the slave, and the other for nothing. So, where i connect in the mono jack, the connection of the ring in the stereo jack??.

Thanks

[Seljer]

1.) If you're not using the DC jack, then the - side of the battery stays as it is. The + side is connected to the same places the red one going from the jack goes.


2.)  If you noticed, when you have a mono connecter (guitar cable) plugged into stereo jack, the ring and sleeve sections are connected together. You may see that the the negative side of the battery is connected to the ring. So when you don't have anything plugged in, the battery is not connected to to the circuit on both sides so you don't end up using it up.

heres a nice writeup by another forumer: http://www.beavisaudio.com/techpages/PedalPower/

[rasco22862]

1.) If you're not using the DC jack, then the - side of the battery stays as it is. The + side is connected to the same places the red one going from the jack goes.


2.)  If you noticed, when you have a mono connecter (guitar cable) plugged into stereo jack, the ring and sleeve sections are connected together. You may see that the the negative side of the battery is connected to the ring. So when you don't have anything plugged in, the battery is not connected to to the circuit on both sides so you don't end up using it up.

heres a nice writeup by another forumer: http://www.beavisaudio.com/techpages/PedalPower/

1) So the wiring goes like this:



2)So i connect the - side of the battery to the sleeve