Removing Gain Control

[MikeH]

I want to remove the gain control from this circuit and hard-wire it to be full gain all of the time (I'm making it into a 1 knob jobby).  Scenario "A" below is how the gain control is currently set up.  It's connected to the Emmiter of a PNP transistor (Q2).  Scenario "C" is how I think it looks with the gain hard-wired at all the way off.  And Scenario "B" is how I believe it to look with the gain hard-wired at all the way up.  Is that right?  And if so, what is the purpose of that electrolytic cap?  Is it just a noise/frequency filter, or is it effecting the gain in some way?  I'm just not sure how this type of gain control works.  It looks like it increases gain by decreasing resistance to ground.  Right?

[d95err]

What circuit are you talking about? (I'm guessing that it is some kind of Fuzz-face derivative)

[petemoore]

  Set the Gain Knob where you want it.
  Measure the pot's resistance or resistances [is it wired with 2 or 3 connections, if 3...measure [and *Note] the R *between the wiper and outside lug, also the *wiper and other outside lug...minding which outside lug went where..
  Replace the position/*those positions with *same value fixed resistors.

[MikeH]

Basically it's the 5th Gear OD from ROG, with some changes.  So, let's say I set the gain to max.  The resistance between 2 and 3 should be zero, and 1 and 2 should be around 5k (value of the pot plus some neglegable amount from the electrolyte).  So basically, I'm bypassing the resistance to ground through the electrolytic cap.  Less resistance to ground = more gain.  But does the value of that cap change anything?