Orange Squeezer Help

Started by mojokicks37, February 19, 2007, 03:41:12 PM

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mojokicks37

Okay, so I know this is a really easy circuit ( I built it on PCB) but I'm just having some problems and I'm frustrated.
I've even walked away and come back and can't do it :(
On my meter, I set it to 20V dcv and connected the black probe to the end of the black cable on the battery snap.

So, here it is. I'd appreciate any help I can get.

1.What does it do, not do, and sound like? Nothing.. when the circuit is bypassed, its the normal signal. When it's activated, I get silence.
2.Name of the circuit = Orange Squeezer (tonepad)
3.Source of the circuit (URL of schematic or project) = http://tonepad.com/project.asp?id=5
4.Any modifications to the circuit? Y or N   Nope
5.Any parts substitutions? If yes, list them.  For the 4558, I used a dual opamp from Radio Shack. LM741CN / 741 OP AMP (Mini DIP IC)
6.Positive ground to negative ground conversion? Y or N  No. Red lead from battery is soldered to the terminal
7.Turn your meter on, set it to the 10V or 20V scale. Remove the battery from the battery clip. Probe the battery terminals with the meter leads before putting it in the clip. What is the out of circuit battery voltage? =>  8.33

Now insert the battery into the clip. If your effect is wired so that a plug must be in the input or output jack to turn the battery power on, insert one end of a cord into that jack. Connect the negative/black meter lead to signal ground by clipping the negative/black lead to the outer sleeve of the input or output jack, whichever does not have a plug in it. With the negative lead on signal ground, measure the following:
Voltage at the circuit board end of the red battery lead = 7.79
Voltage at the circuit board end of the black battery lead =

Now, using the original schematic as a reference for which part is which (that is, which transistor is Q1, Q2, etc. and which IC is IC1, IC2, C1, and so on) measure and list the voltage on each pin of every transistor and IC. Just keep the black lead on ground, and touch the pointed end of the red probe to each one in turn. Report the voltages as follows:

Q1 - 2n5457 (top)
G = 7.99
S = 7.99
D = 8.00

Q2 - 2n5457 (bottom)
G= 8.04
S= 8.02
D= 8.02

IC1 (or U1) - 741 OP AMP (Mini DIP IC)
P1 - V-  - 8.13
P2 - Non-invert input - 7.39
P3 - Invert input - 7.57
P4 - Offset null - 8.15
P5 - offset null - 8.03
P6 - output - 8.04
P7 - V+ - 0.00
P8 - NC - 0.00

D1
A (anode, the non-band end) = 0.00
K (cathode, the banded end) = 0.00     

i think the diode may be the problem. i'm checking for cold solder joints, as i feel like i may have a sizeable amount.

please let me know if you can help or if you need more information.
"I'm always thinking about creating. My future starts when I wake up every morning . . . Every day I find something creative to do with my life."

"For me, music and life are all about style."

cab42


I may be wrong, but are you sure that a 741 and 4558 is pin to pin compatible?  As far as i remember the 741 is a single opamp.

If you look in the FAQ (http://www.diystompboxes.com/wiki/index.php?title=DIY_FAQ#OP_AMP) it seems that the pinouts are different.

Someone, correct me if I'm wrong

Regards

Carsten

  • SUPPORTER
"Rick, your work is almost disgusting, it's so beautiful.  Meaning: it's so darned pretty that when I look at my own stuff, it makes me want to puke my guts out."
Ripthorn

snoof

#2
you are correct sir!  741 is a single, 4558 is a double.  but it looks as if the circuit is only using 1/2 the 4558.  so the pinout on the schem would need to be changed.  pinout for 741 is 1=offset, 2=-, 3=+, 4=Grnd, 5=offset, 6=out, 7=V+, 8=NC.  so you have the chip hooked up wrong.

mojokicks37

that could explain why it got hot?
"I'm always thinking about creating. My future starts when I wake up every morning . . . Every day I find something creative to do with my life."

"For me, music and life are all about style."

cab42


Quote from: snoof on February 19, 2007, 04:39:51 PM
you are correct sir!  741 is a single, 4558 is a double.  but it looks as if the circuit is only using 1/2 the 4558. 

I remember seeing a dual squeezer at ustomp.com using each half of the 4558 for two OS in series on one board.

Quote from: mojokicks37 on February 19, 2007, 05:09:12 PM
that could explain why it got hot?

I suddenly remembered how I knew this. I once build a tube reamer using a 741 but ruined the perfboard while modding. I then rebuild it using another layout recycling the 741, but did not notice that the layout used one half of a dual opamp instead. Result: a fried 741 (and yes - it got hot :))

Regards

Carsten
  • SUPPORTER
"Rick, your work is almost disgusting, it's so beautiful.  Meaning: it's so darned pretty that when I look at my own stuff, it makes me want to puke my guts out."
Ripthorn

markm

Quote from: cab42 on February 19, 2007, 05:56:24 PM

Quote from: snoof on February 19, 2007, 04:39:51 PM
you are correct sir!  741 is a single, 4558 is a double.  but it looks as if the circuit is only using 1/2 the 4558. 

I remember seeing a dual squeezer at ustomp.com using each half of the 4558 for two OS in series on one board.

Quote from: mojokicks37 on February 19, 2007, 05:09:12 PM
that could explain why it got hot?

I suddenly remembered how I knew this. I once build a tube reamer using a 741 but ruined the perfboard while modding. I then rebuild it using another layout recycling the 741, but did not notice that the layout used one half of a dual opamp instead. Result: a fried 741 (and yes - it got hot :))

Regards

Carsten

That's not good!  :(