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TS9 tone control

Started by Nikolay, March 18, 2007, 02:51:07 PM

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Nikolay

Hi, witch elements value I must change to use 50k pot instead the original 20k pot without any sound differences?

Thanks :)

rosssurf

I am kind of new at this but. Could you just solder a 25 resistor on the the 50 K and make it a 25K. I was curious about this as well since I am looking to make a Tube screamer but am having a hard time finding 20K pots

WelshWonder

I used the more common 22k value and they worked fine.

Nikolay

Quote from: rosssurf on March 18, 2007, 02:58:00 PM
I am kind of new at this but. Could you just solder a 25 resistor on the the 50 K and make it a 25K. I was curious about this as well since I am looking to make a Tube screamer but am having a hard time finding 20K pots

rosssurf this is not a good idea. This will make linear pot to S-curve pot. The pot will work only at the beginning and at the end. At the center area will not change the sound.
I think that if I must multiple pot valu by 2.5 (from 20k to 50k), I must divine 220ohm resistor to 550 and divide 220n capacitor to 2.5 = 88n. But I'm not sure...

markm


Nikolay

Mark I don't like to use 20k pot. I like to use pots from the local electronic shop.  :icon_rolleyes:

George Giblet

You can scale all the parts my multiplying all resistors by (50/20) and all caps by (20/50); that includes the 1k and 220nF at the input.

Did you know the original pot is a 20kG  the G means it's a "funny" graphic equalizer taper?  What that does is smooth out the control reducing crowding at the end of the control - it doesn't change the tone over a 20kB linear pot.

Another thing you can do is use a 50k and two 18k resistors.  You connect one 18k between pot terminals  1 & 2 and another between terminals 2 & 3.  With this method there is virtually *no difference* in the response compared to a 20k pot, however the control at the ends becomes about twice as crowded as a 20kB linear pot - ie. worse crowding.