50k for a 25k?

[foozertone]

I'm working on anEA tremelo and I was wondering if I could use a 50k pot for a 25k? I think I can but I just want to be sure. Sorry for such a basic question.

Thanks

Jeff

[CGDARK]

Try to test the circuit with the 50k, if it do what you want, you can go with, if not you'll need the 25k. Remember this is a matter of taste and in order to learn you have to test, test and test so you can tell yourself in the future what's wrong or right for a given circuit.

CG

[foozertone]

Okay  that's a good idea. I'm alittle gun-shy because I haven't been able to get anything working yet. I'm still tryin' though.

Thanks

Jeff

[SonicVI]

Or, if you happen to have a 50K resistor you can solder it to the outside lugs of the 50K pot to make it a 25K pot.

[foozertone]

That's an even better idea. Why does that work?

Thanks

Jeff

[carrejans]

That's an even better idea. Why does that work?

Thanks

Jeff

http://www.physics.uoguelph.ca/tutorials/ohm/Q.ohm.intro.parallel.html

[jasonsmusicgear]

Or, if you happen to have a 50K resistor you can solder it to the outside lugs of the 50K pot to make it a 25K pot.

That is very good to know, is it possible to make a 25k pot into a 50k?

[SonicVI]

No, all you could do is put a 25K resistor in series with a 25K pot to get up to 50K, but then you're minimum resistance would be 25K, not 0.

[Shakal]

You can put a 50k Resistor in paralell with the 50K pot. It WILL NOT be the same as a 25k pot, but will be close.

Heres is a comparison of what it should be first and what is going to be next.

25K = 25K
20K = 22K
15K = 18.75K
10K = 14.3K
5K = 8.3K
2.5K = 4.54K
1K = 1.9K
0K = 0K ( )

As u can see, it works better a first. You should try it, its better than use just the 50K pot.

Therefore if what you have is a Log Pot... Errrr... I have no $¾óþå idea what is going to happen.