Newbie stuck

Fragrag · August 16, 2007, 03:44:49 PM

Hello, I'm an electronics newbie stuck on building a pedal.

I'm building the Bazz Fuss. However, I made all this but I'm currently stuck. I can't find a schematic that corresponds to this, others seem to be just a bit off. I'm basing myself on this other fuzz design to help me. Let me sum up the questions:

From Level 2 there's a connection to somewhere unnoted, is this to the footswitch?
What connections are the ground connections?
Capacitor 3, or the one of 22µF, what's its polarity?
The transistors, are they supposed to be positioned like that? Flat side to the right?

Thanks in advance!

-Haryo Sukmawanto

snoof · August 16, 2007, 03:59:51 PM

lug 2 goes to output jack tip. Ground plane is around the perimeter. the shaded portion of C3 is ground.

Pushtone · August 16, 2007, 04:10:21 PM

Quote from: snoof on August 16, 2007, 03:59:51 PM

lug 2 goes to output jack tip.

Yes your right Fraqag.
Take lug 2 to the output side of your footswitch, then to the output jack tip like Snoof said.

Looks like MarkM has given us three spare ground pads to connect to what needs grounding.
You can also take ALL grounds to the output jack sleeve and use only one wire from the board for grounding.
As in star grounding.

Good luck.

Fragrag · August 16, 2007, 04:32:35 PM

Wow, mighty quick replies, thanks guys, I'll work on this tomorrow. Thanks!

snoof · August 16, 2007, 04:33:11 PM

right, oops. to the output jack after the switch

.

Fragrag · August 16, 2007, 06:00:18 PM

Quote from: Pushtone on August 16, 2007, 04:10:21 PM

Looks like MarkM has given us three spare ground pads to connect to what needs grounding.
You can also take ALL grounds to the output jack sleeve and use only one wire from the board for grounding.
As in star grounding.

I'm sorry, but what? Precisely which pads are ground? The ones unmarked? What do I do then, connect them all? And what do you mean the shaded part of C3 is ground, does that mean it's negative (sorry that I ask these questions a bit later, but I just noticed htem :p)

GREEN FUZ · August 16, 2007, 06:38:48 PM

In Mark`s layout the outer trace is the ground, that`s the slightly fatter U-shaped line that forms the perimeter. The holes are the pads.

A good layout designer, in my opinion, includes extra ground pads in their design for the possible inclusion of supplementary components. That doesn`t go to say they all need to be used they are simply there as a contingency.

Yes the shaded part of C3 is the negative which is donated by the stripe on one side of your capacitor. Hope this helps. If not it`s my fault for not explaining properly so don`t hesitate to ask more questions.

Fragrag · August 16, 2007, 07:02:27 PM

Thank you, and the transistors, I put them like they are in the layout, flat side to the left, because as far as I can see, there is no indication of collector, base nor emitter. Does anyone also know the schematic for this? That might clear things up for me.

GREEN FUZ · August 17, 2007, 06:53:58 AM

Usually the transistor will work as indicated by the layout but not all trannies have the same pinout so you may have to check the datasheet to confirm this.

Fragrag · August 20, 2007, 10:24:39 AM

Sorry for the bump, but this doesn't warrant a new thread. What goes into the 'IN'? Potmeter? Sleeves of the jacks?

petemoore · August 20, 2007, 10:52:31 AM

Sorry for the bump, but this doesn't warrant a new thread. What goes into the 'IN'? Potmeter? Sleeves of the jacks?
The sleeves of the jacks are almost always assigned to ground [especially when labeled and wired as 'input or output' jacks.
Something labeled 'IN' would most likely carry signal, and...I can't tell more for sure cause I'm lazy..probably the flow is...from guitar cable to input jack tip, input jack tip lug to a Switch lug [for input bypass or to circuit] then from the input to curcuit lug of the switch to the circuit input.
0---0
Guitar cable > injack tip > tiplug to Switch I 0out
0
Goes to circuit board input
The top left and top right 'O's show the bypass jumper across the signal switching portions of the switch [3pdt have 1 more column of lugs to the right or left...so that'd be the dpdt signal path switching portion, 6 lugs]
the bottom 'O' is what would have a wire to the circuit board input.
I didn't have room to type in the bottom right corner 'O', which would go to the output jack.
The middle right lug is the switch output, depending on whether the switch is in bypass or effect mode, the signal would go in the middle left, and out the middle right lug. In effect mode the bottom left lug to circuit board input, the bottom right lug to circuit board output [these are the input and output lugs of a switch assigned to true bypass..er a common way to do it].
Depending on the switches mode, the signal would travel across the top jumper, or across the two bottom lugs [through the effect circuit].
Jumper
0---------0
Input jack tip0 0-output jack tip
Circuit input-0 0-circuit output

Fragrag · August 20, 2007, 10:55:50 AM

Wow, thanks a lot for taking your time to write that. So it goes opposite of output switch where lug 2 is connected? Also, do I need a stereo cable to connect from my guitar to the pedal?

petemoore · August 20, 2007, 12:58:09 PM

So it goes opposite of output switch where lug 2 is connected?
What is 'it'...
Unless you have wiring to support stereo signal input, I would suggest using Mono Phono 1/4'' plugs to connect, especially if you have input power defeat / stereo jack trick wired up, this would allow power to get through the ring/sleeve of your input jack to the circuit...
The sleeve of the mono plug connects the ring and sleeve of the stereo jack, or opens the connection when pulled out.

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Newbie stuck