Math test help: (real input is 43K || 470K || hfe x 390 ohms)

Started by petemoore, February 08, 2008, 02:58:05 PM

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petemoore

  And I can't pass my own test.
   (real input is 43K || 470K || hfe x 390 ohms)
  Gus provided this equation in regards to a 2n5088 with a 43k/470k bias string and 390ohm resistor.
   I understand how it works functionally, and how the bias string resistance can 'adjust the math' on the input impedance, but when working the ohms math I lose the decimal point !
  Lets call the impedance 1000hfe [just for a round number], and make the emitter resistor on the Bipolar transistor 100ohms.   
  1000 x 100 = 100,000...seems high
  that number can be practically disregarded when it's to be paralleled with a 43k.
  I understand the ll = parallel,
  ..and 43k ll 470k would be less than 43k by a 'bit'...I can grab a 43k and parallel a 470k and get a DMM read...or guess say about mid 30's-K ish, close enough to decide whether more suitable resistors should be sought out to adjust input impedance.
  I would like to work through the math and apply it.
   
Convention creates following, following creates convention.

stm

Pete,

100,000 ohms compared to 43,000 ohms is not insignificant!  It reduces impedance down to 30,000 ohms.

Also, hfe for a 2N5088 is closer to 500 rather than 1000.  Then, for the original problem you have a 500*390 = 195,000 base impedance.

Making the total calculation: Req = 1 / ( 1/43 + 1/195 + 1/470 ) = 32.77 kohms.



Hfe would be 500 rather than 1000

petemoore

100,000 ohms compared to 43,000 ohms is not insignificant!  It reduces impedance down to 30,000 ohms.
  That's great, my ballparking ability went right out the window when I started looking harder at the math...
  Also, hfe for a 2N5088 is closer to 500 rather than 1000.  Then, for the original problem you have a 500*390 = 195,000 base impedance.
  Making the total calculation: Req = 1 / ( 1/43 + 1/195 + 1/470 ) = 32.77 kohms.
   My math is terrible, I'm now confused by that ^. Oh man, I don't know where to start asking now.
  'R' means resistor
  'E' means emitter
  so 'Re' means resistance of the emitter resistor and emitter?
  'q' .... hmmm....hmmm
  '=' means equals...
  '1' again hmmm.
  '/' means divided by
  '[  ]..in parenthesis' means work these numbers and signs first.
  '+' means plus or add.
   Hfe would be 500 rather than 1000 yes, 500 is another good round number and closer to the actual Hfe you'd find in a typical 5088.
 
Convention creates following, following creates convention.

johngreene

Quote from: petemoore on February 08, 2008, 03:24:46 PM
100,000 ohms compared to 43,000 ohms is not insignificant!  It reduces impedance down to 30,000 ohms.
  That's great, my ballparking ability went right out the window when I started looking harder at the math...
  Also, hfe for a 2N5088 is closer to 500 rather than 1000.  Then, for the original problem you have a 500*390 = 195,000 base impedance.
  Making the total calculation: Req = 1 / ( 1/43 + 1/195 + 1/470 ) = 32.77 kohms.
   My math is terrible, I'm now confused by that ^. Oh man, I don't know where to start asking now.
  'R' means resistor
  'E' means emitter
  so 'Re' means resistance of the emitter resistor and emitter?
  'q' .... hmmm....hmmm
  '=' means equals...
  '1' again hmmm.
  '/' means divided by
  '[  ]..in parenthesis' means work these numbers and signs first.
  '+' means plus or add.
   Hfe would be 500 rather than 1000 yes, 500 is another good round number and closer to the actual Hfe you'd find in a typical 5088.
 
There's no smiley face so I'm not sure if you are kidding or not. Req means R(equivalent). Meaning the total resistance or input impedance.

'^' means raised to the power of. i.e. 5^2 is 5 squared.
I started out with nothing... I still have most of it.

petemoore

There's no smiley face so I'm not sure if you are kidding or not. Req means R(equivalent).
   :)
  But seriously, possibly stumped, perhaps just more of a "Doh" type thing though.
  I really think I 'get' it.. generally and basically..the numbers just aren't clicking'.
  '^' means raised to the power of. i.e. 5^2 is 5 squared.
  I was using it as an 'up' pointer, to the line of text above '^'.
   Req = 1 / ( 1/43 + 1/195 + 1/470 ) = 32.77 kohms.
  1/43 = .02325xxxx
  1/195 = .00512xxxxetc.
  1/470 = .0021xxx
  .0235 + .0051 + .0021 = .2386
  1/.2386 = 4.19111
  Here I've worked the parenthesis equation first using '/' on the calculator where /'s are..., then worked that sum as 1/x and got 4.19111xxxxxxxxxxxxxxxxxxx
  Of course that doesn't look like it's even in the same city as the ballpark.. :icon_eek:
 
  . 
 
 
Convention creates following, following creates convention.

johngreene

Quote from: petemoore on February 08, 2008, 05:50:07 PM
There's no smiley face so I'm not sure if you are kidding or not. Req means R(equivalent).
   :)
  But seriously, possibly stumped, perhaps just more of a "Doh" type thing though.
  I really think I 'get' it.. generally and basically..the numbers just aren't clicking'.
  '^' means raised to the power of. i.e. 5^2 is 5 squared.
  I was using it as an 'up' pointer, to the line of text above '^'.
   Req = 1 / ( 1/43 + 1/195 + 1/470 ) = 32.77 kohms.
  1/43 = .02325xxxx
  1/195 = .00512xxxxetc.
  1/470 = .0021xxx
  .0235 + .0051 + .0021 = .2386
  1/.2386 = 4.19111
  Here I've worked the parenthesis equation first using '/' on the calculator where /'s are..., then worked that sum as 1/x and got 4.19111xxxxxxxxxxxxxxxxxxx
  Of course that doesn't look like it's even in the same city as the ballpark.. :icon_eek:
I understand now! doh.

um, I don't think .0235 + .0051 + .0021 = .2386.  I get 0.0305..  and if you take 1/0.0305... you get 32.77...

The only way I can get .2386 is if I leave a '0' out of .0235 and transpose the 1 and 5 in .0051. So .235 + .0015 + .0021 = .2386  :icon_eek:

--john
I started out with nothing... I still have most of it.