Passive switching question

[C.A.E.]

Does anyone know if this setup will work without a pop?  The middle jack is output, other two or inputs.  The center wire goes to voltage +.  two leds go two voltage -.  The switch will select between two inputs with an led indicating which one is active.  And the jack wires go to the first set of lugs.   

[Alex C]

That's kind of confusing to look at and then apply the clarifications and corrections you mentioned.

If the jacks are going to the far left lugs, the output (center) should connect to either the top or the bottom jack depending on the state of the switch, so that part should work.

You said "the center wire goes to voltage +."  The LEDs will not light if it is wired this way.  The LEDs need to have a current-limiting resistor (around 2.2k or so, depending on the desired brightness and current consumption) connected between V+ and the "top" of each LED as they are viewed in the image.  The side with the FLAT marking (and the FLAT part of the actual component) will go to ground (what you're calling "voltage -").

You shouldn't get any pop due to the LEDs, as you're not connecting the signal to any active circuitry.


-Alex

[C.A.E.]

Yea, I realized that the leds were backwards after I did it.  So would it work if I hook top right and bottom right lugs to led via a resistor and hook the other end of led to ground? (leaving the positive hooked to center lug)