a good way to switch between 3 or 4 signals with an lfo or pulse?

[loss1234]

I'd like to take 3 or 4 different paths (lets say and octave down, 2 octaves down, and a distorted channel, and switch between them using the divide by 12 (which is really slow enough to be a high low signal) signal as the control input to whatever system could do this. I was hoping something like the 4016 could do this, but it seems to only be able to turn a channel On or Off not switch between a and b.

any ideas?

the 4051-4053 looked promising but they have THREE control inputs so i dont know how i could approach that.

I remember seeing a diagram for a distortion that did this very thing, it switched between two distortion paths. it said it could be done with a 4066 but i dont see how.


any help appreciated.


thanks

[frequencycentral]

Hi loss

You could use say a 4017 or a 4022 to step through the four switches in the 4016/4066.

If you just want to switch between two, use half a 4013.

[loss1234]

hmmm, how can i use the 4017 to switch  between the switches on a 4016? it sounds good but the concept doesnt quite click. In cmos cookbook, he says the 4016 CAN be used as a 1 0f 4 data selector if you wire the switches together, but he doesnt show HOW to do this.

maybe its time to google.

thanks

[frequencycentral]

The 4017 has 10 outputs.

Wire 0, 1, 2 and 3 each to an input of the 4016.

Wire output 4 of the 4017 to its 'reset' - then it will just step through 0 to 3, and reset on 4.

Each step will open a switch on the 4016.

[loss1234]

thanks

great idea!

[MadMac]

wow this sounds like an awesome idea - when I get some time I might have to try this

[frequencycentral]

thanks

great idea!

wow this sounds like an awesome idea - when I get some time I might have to try this

Glad to be of help!

[R.G.]

4024 -> 4051; any three sequential outputs count through all eight states and provide one of eight on the 4051
analog LFO -> LM3914 -> 4066(s); 3914 converts analog to one of 10; wire up single switches to outputs. May have to use inverters to get sense right.

[frequencycentral]

R.G.

I'm struggling to get my head round this:

4024 -> 4051; any three sequential outputs count through all eight states and provide one of eight on the 4051
analog LFO -> LM3914 -> 4066(s); 3914 converts analog to one of 10; wire up single switches to outputs. May have to use inverters to get sense right.

I've used a few 4024 chips as clock dividers in my modular. Are you saying that the 4024 outputs provide a (binary) driver for the 4051?

I need to do some research!

[R.G.]

The 4024 is a many-stage binary divider. Any three adjacent outputs count in binary from 000 ... 111, 000 . If you put those outputs into the A, B, C select pins of the 4051, it selects output 0, 1, 2...7, 0 and all over again. Any binary counter counts in the sequence that the 4051 needs to select outputs in order.