Talk to me about bridging pots with resistors...........

[MrStab]

really glad this thread was bumped - whenever i try to find definitive info on just bridging the outer lugs of a pot, i can only find info on bridging lugs next to each other. so thanks for the graphs & schematics, guys - really informative. Ctrl+D!

[fishfude]

Right I'm super duper confused! Why bother connect to leg 3 (the ground leg) at all - It seems like unnecessary wiring? Why not just connect legs one and two to the circuit (we're just using the pot as a series resistor right?) and if you want to taper it, put the appropriate resistor across those legs in parallel?

Please enlighten me

Cheers,

ff

[PRR]

> Why bother connect to leg 3

Some day the wiper (pin 2) will lose contact with the pot resistor.

Tying the "unused" pin means when that happens it only goes to "10" instead of to infinity.

Depending on the circuit, this may or may not matter much.

It really is easier to bend some extra wire to the idle pin and solder than to think about how it would go wrong.

[fishfude]

Ok I get it, its not necessary, it's just prudent!

Thanks PRR!

[victor nery]

please delete this. sorry for the trouble.

[Baran Ismen]

Am I too stupid to comprehend this matter or my pots are just weird?

http://web.archive.org/web/20210203023928/https://www.elby-designs.com/webtek/documents/tailoringpotentionometers.pdf

According to this PDF file's 5th Figure, I need to solder a 100k resistor between 2 active lugs of my 1m linear pot and it becomes logarithmic, right?

Mine becomes however something completely different, it reads around 80k or something. For Rev.Log, what shall I do? Add a resistor of 10m?

Thing is, the circuit I deal with right now is Small Stone and there are only 2 lugs connected. 3rd one is empty, or shorted to 2nd.

[antonis]

Could you plz stop duble-posting.?