Decreasing input volume

Started by jonathansuhr, July 11, 2011, 01:19:13 AM

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jonathansuhr



Built this a long time ago, but I only like the sound of the pedal with the input control backed way off and the volume on my guitar at about 60%. So I was thinking, would wiring a resistor in series with the input produce the same result as having my guitar volume backed off?

artifus

try an input pot connected just as the output pot is shown connected - outer lugs to signal and ground, centre lug to input.

jonathansuhr

I don't have room for an additional pot unfortunately as it's a 1590a build.

So I should add, I negated the input cap and used a 100K pot I had on hand for the input stage. I like the sound of the pedal with the pot at 0 and my guitar at about 60%. But I want to be able to use the pedal with my guitar's volume at full.

Would the inclusion of the input cap help offset some of the gain?

And couldn't I just add a resistor immediately after the input to simulate a lowered guitar volume?

artifus

#3
not familiar with this circuit, series input resistor may work, suck it and see. if not then a voltage divider, which is what the suggested input pot would create, made up of two resistors - one in the signal path and another immediately after it going to ground. you'll have to do some maths or experiment to find the correct values for the attenuation you are after if you don't want a pot. a space saving internal trim pot maybe?

QuoteI negated the input cap and used a 100K pot I had on hand for the input stage. I like the sound of the pedal with the pot at 0 and my guitar at about 60%

so the pot is not in use - it is simply connecting the input to whichever of the two caps is at '0' on the pot. use that pot as your input voltage divider with the wiper feeding whichever cap you prefer the sound of. maybe you could squeeze in a switch to choose between the two caps.